已知:[(x的平方+y的平方)-(x-y)的平方+2y(x-y)]/4y=1,求4x的平方-y的平方分之4x-2

已知:[(x²+y²)-(x-y)²+2y(x-y)]/4y=1,求4x²-(4x-2)/y²[(x²+y²)-(x-y)²+2y(x-y)]/4y＝[2xy+2y(x-y)] /4y=(4xy-2y²)/4y=(4x-2y)/4=1即2x=y+2,故4x²-(4x-2)/y²＝(2x)²-2(2x-1)/y²=(y+2)²-2(y+1)/y²【原题有错!】 再问： 谢谢你哈