求lim[sinx(ex-1)/1-cosx+ln(1+x)/tanx]

运用极限的运算性质lim(x→0)[sinx(e^x-1)/(1-cosx)+ln(1+x)/tanx]=lim(x→0)sinx(e^x-1)/(1-cosx)+lim(x→0)ln(1+x)/tanx=lim(x→0)x^2/(1/2x^2)+lim(x→0)x/x=2+1=3