当a=根号3时,求[(1-2a+a^2)/(a-1)]-(根号[a^2-2a+1])/(a^2-a)

a=√3>1a-1>0|a-1|=a-1原式=[(a-1)²/(a-1)]-√(a-1)²/a(a-1)=(a-1)-|a-1|/a(a-1)=a-1-(a-1)/a(a-1)=a-1-1/a=√3-1-1/√3=2√3/3-1