1.集合A={(x,y)｜x∧2+mx-y+2=0},集合B={(x,y)｜x-y+1=0,且0≤X≤2}

1.集合A={(x,y)｜x∧2+mx-y+2=0},集合B={(x,y)｜x-y+1=0,且0≤X≤2}又A∩B≠空集,求实数m的取值范围2.当x=__时,函数f(x)=(x-a1)∧2+(x-a2)∧2+……+(x-an)∧2取得最小值3.对于任意函数,函数f(x)=(5-a)x∧2-6x+a+5恒为正值,求a的取值范围4.已知函数y=f(x)的图像关于直线x=-1对称,且当x属于（0,+∞）时,有f(X)=1/x ,则当x属于(-∞,-2)时,f(x)的解析式A -1/x B.-1/(x-2) C.1/(x+2) D.-1/(x+2)