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极限lim(n->∞) n^(2/3)/[(n^2+n+7)^1/3]=1

学习时间:2026-04-04 20:52:51 阅读：7574

极限lim(n->∞) n^(2/3)/[(n^2+n+7)^1/3]=1

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2026-04-04 20:52:51

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变换为(n^(2/3)/[(n^2+n+7)^1/3])^(3*(1/3) )变换为(n^2)/[(n^2+n+7)]^(1/3) 变换为(1)/[(1+(1/n)+(7/n))]^(1/3) 变换为(1)/[(1+(0)+(0))]^(1/3) 1

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2026-04-04 20:52:51
变换为(n^(2/3)/[(n^2+n+7)^1/3])^(3*(1/3) )变换为(n^2)/[(n^2+n+7)]^(1/3) 变换为(1)/[(1+(1/n)+(7/n))]^(1/3) 变换为(1)/[(1+(0)+(0))]^(1/3) 1

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