用lingo实现,y（i）=y（j）时,x（i）不等于x（j）?

学习时间:2026-04-06 21:08:35 阅读：2607

用lingo实现,y（i）=y（j）时,x（i）不等于x（j）?大哥大姐们：请问用lingo如何实现y（i）=y（j）时,x（i）不等于x（j）?lingo有这个功能吗?我试过了,但是不行,我的现有程序是：MODEL:data:M=7;enddatasets:demand/1..m/:p,a,d,x,y;ob/1..m/:w;endsetsdata:p=5,3,5,6,7,12,8;a=3,4,4,1,5,8,8;d=5,6,6,3,7,9,10;enddata[OBJ] min=@sum(demand(i):2*@abs(x(i)-p(i))+3*@abs(y(i)-a(i)));@for(demand(i):y(i)>a(i);y(i)1); @for(demand(i):@gin(x(i)));@for(demand(i):@gin(y(i)));end怎么用程序表示当y相同时,x不同?

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清爽的草丛

2026-04-06 21:08:35

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改了一点,在逻辑上没有问题,但是就不是线性模型了,用全局最优器解。你看看吧!MODEL:data:M=7; enddata sets:demand/1。。m/:p,a,d,x,y; ob/1。。m/:w; link(demand,demand):aa; endsets data:p=5,3,5,6,7,12,8; a=3,4,4,1,5,8,8; d=5,6,6,3,7,9,10; enddata [OBJ] min=@sum(demand(i):2*@abs(x(i)-p(i))+3*@abs(y(i)-a(i))); @for(demand(i):y(i)>a(i); y(i)1); @for(demand(i):@gin(x(i))); @for(demand(i):@gin(y(i))); @for(demand(i):@for(demand(j)|j #ne# i:x(i)+y(i)=x(j)+y(j)+aa(i,j))); @for(demand(i):@for(demand(j):@free(aa(i,j)))); @for(link:@free(aa));@for(link:aa*aa>0); end

用lingo实现,y（i）=y（j）时,x（i）不等于x（j）?

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