已知(a+2)^2+|b+3|=0,求3a^2b-[2a^2b-(2ab-a^2b)-4a^2]-ab的值

(a+2)^2+|b+3|=0则：a+2=0,b+3=0得：a=-2,b=-3原式=3a²b-(2a²b-2ab+a²b-4a²)-ab=3a²b-3a²b+2ab+4a²-ab=4a²+ab把a=-2,b=-3代入得：原式=22