计算[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y

学习时间:2026-09-27 12:48:14 阅读：5599

计算[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y如题

暴躁的犀牛

2026-09-27 12:48:14

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[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y=(x^3y^2-x^2y-x^2y+x^3y^2)/3x^2y=(2x^3y^2-2x^2y)/3x^2y=2x^3y^2/3x^2y-2x^2y/3x^2y=(2xy-2)/3