计算[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y

学习 时间:2026-04-01 08:55:30 阅读:2451
计算[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y如题

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2026-04-01 08:55:30

[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y=(x^3y^2-x^2y-x^2y+x^3y^2)/3x^2y=(2x^3y^2-2x^2y)/3x^2y=2x^3y^2/3x^2y-2x^2y/3x^2y=(2xy-2)/3

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  • 魁梧的微笑
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    2026-04-01 08:55:30

    [x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y=(x^3y^2-x^2y-x^2y+x^3y^2)/3x^2y=(2x^3y^2-2x^2y)/3x^2y=2x^3y^2/3x^2y-2x^2y/3x^2y=(2xy-2)/3

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