计算[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y

学习时间:2026-08-13 07:20:42 阅读：43

计算[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y如题

苹果月亮

2026-08-13 07:20:42

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[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y=(x^3y^2-x^2y-x^2y+x^3y^2)/3x^2y=(2x^3y^2-2x^2y)/3x^2y=2x^3y^2/3x^2y-2x^2y/3x^2y=(2xy-2)/3