设实数x,y满足x^2+y^2+8x+6y+25=0,求(x^2-4y^2)/(x^2+4xy+4y^2)-x/x+2y

学习 时间:2026-11-12 11:07:56 阅读:1416
设实数x,y满足x^2+y^2+8x+6y+25=0,求(x^2-4y^2)/(x^2+4xy+4y^2)-x/x+2y的值.

最佳回答

危机的犀牛

会撒娇的金鱼

2026-11-12 11:07:56

x^2+y^2+8x+6y+25=(x+4)^2+(y+3)^2=0则x+4=0y+3=0(x^2-4y^2)/(x^2+4xy+4y^2)-x/(x+2y)=[(x+2y)(x-2y)]/(x+2y)^2-x/(x+2y)=(x-2y)/(x+2y)-x/(x+2y)=-2y/(x+2y)=6/-10=-3/5

最新回答共有2条回答

  • 隐形的斑马
    回复
    2026-11-12 11:07:56

    x^2+y^2+8x+6y+25=(x+4)^2+(y+3)^2=0则x+4=0y+3=0(x^2-4y^2)/(x^2+4xy+4y^2)-x/(x+2y)=[(x+2y)(x-2y)]/(x+2y)^2-x/(x+2y)=(x-2y)/(x+2y)-x/(x+2y)=-2y/(x+2y)=6/-10=-3/5

上一篇 The climate here is quite different from ---of shenyang.

下一篇 BIG TIME是什么