X+1)除以（x+2）加上（x+6）除以（x+7）等于（x+2）除以（x+3）加上（x+5）除以（x+6）

(X+1)除以（x+2）加上（x+6）除以（x+7）等于（x+2）除以（x+3）加上（x+5）除以（x+6） [1-1/(x+2)]+[1-1/(x+7)]=[1-1/(x+3)]+[1-1/(x+6)] 1/(x+2)+1/(x+7)=1/(x+3)+1/(x+6) (2x+9)/(x+2)(x+7)-(2x+9)/(x+3)(x+6)=0 (2x+9)(1/(x+2)(x+7)-1/(x+3)(x+6))=0 (2x+9)[(x^2+9x+18)-(x^2+9x+14)]/(x+2)(x+7)(x+3)(x+6)=0 4(2x+9)/(x+2)(x+7)/(x+3)(x+6)=0 2x+9=0 x=-9/2