a^2b^2c-abc+1/4c;a^2(x-y)+b^2(y-x);

学习 时间:2026-05-30 21:39:28 阅读:2767
a^2b^2c-abc+1/4c;a^2(x-y)+b^2(y-x);

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悲凉的含羞草

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2026-05-30 21:39:28

a^2b^2c-abc+1/4c=c(a^2b^2-ab+1/4)=c(ab-1/2)^2;a^2(x-y)+b^2(y-x)=a^2(x-y)-b^2(x-y)=(x-y)(a^2-b^2)=(x-y)(a+b)(a-b)。

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  • 文艺的麦片
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    2026-05-30 21:39:28

    a^2b^2c-abc+1/4c=c(a^2b^2-ab+1/4)=c(ab-1/2)^2;a^2(x-y)+b^2(y-x)=a^2(x-y)-b^2(x-y)=(x-y)(a^2-b^2)=(x-y)(a+b)(a-b)。

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