1.解分式方程:1/(x+2)+1/(2x+3)+1/(3x-4)1/（6x+1）求答案

1/(x+2)+1/(2x+3)=1/(6x+1)-1/(3x-4)2x+3+x+2/(x+2)(2x+3)=3x-4-6x-1/(6x+1)(3x-4)3x+5/(x+2)(2x+3)=-(3x+5)/(6x+1)(3x-4)(x+2)(2x+3)=-(6x+1)(3x-4)2x^2+7x+6=-(18x^2-21x-4)20x^2-14x+2=0(10x-2)(2x-1)=0x1=1/5,x2=1/2