数学题找人解决!-3x²+4x+1=01/2x²+2x-1=03x²-12x+1/3=02

-3x²+4x+1=03x²-4x-1=0x = {4±根号(4^2+4*3)}/(2*3)={2±根号7} /3x1 = (2-根号7) /3x2 = (2+根号7) /31/2x²+2x-1=0x²+4x-2=0(x+2)²=2+4x+2=±根号6x1=-2-根号6x2=-2+根号63x²-12x+1/3=0x²-4x+1/9=0(x-2)²=4-1/9x-2=±根号35 /3x1 = 2-根号35 /3x2 = 2+根号35 /32x²+2。5x-0。5=04x²+5x-1=0x= {-5±根号(5^2+4*4)}/(2*4) = {-5±根号41)}/8x1={-5-根号41)}/8x2={-5+根号41)}/8