1/(1*3)+1/(3*5)+1/(5*7)+...+1/(97*99)+1/(99*101)谁帮忙解一下!

学习 时间:2026-04-01 08:42:16 阅读:2164
1/(1*3)+1/(3*5)+1/(5*7)+...+1/(97*99)+1/(99*101)谁帮忙解一下!

最佳回答

紧张的乐曲

欣慰的铅笔

2026-04-01 08:42:16

1/(1*3) + 1/(3*5) + 1/(5*7) + 。+ 1/(97*99) + 1/(99*101) = (1-1/3)/2 + (1/3 - 1/5)/2 + (1/5-1/7)/2 + 。+ (1/97-1/99)/2 + (1/99-1/101)/2 = [(1-1/3) + (1/3 - 1/5) + (1/5-1/7) + 。+ (1/97-1/99) + (1/99-1/101)] / 2 = [(1+1/3+1/5+。+1/97+1/99) - (1/3+1/5+1/7+。+1/99+1/101)] / 2 = [ 1 - 1/101] / 2 = [100/101] / 2 = 50/101

最新回答共有2条回答

  • 动听的哈密瓜,数据线
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    2026-04-01 08:42:16

    1/(1*3) + 1/(3*5) + 1/(5*7) + 。+ 1/(97*99) + 1/(99*101) = (1-1/3)/2 + (1/3 - 1/5)/2 + (1/5-1/7)/2 + 。+ (1/97-1/99)/2 + (1/99-1/101)/2 = [(1-1/3) + (1/3 - 1/5) + (1/5-1/7) + 。+ (1/97-1/99) + (1/99-1/101)] / 2 = [(1+1/3+1/5+。+1/97+1/99) - (1/3+1/5+1/7+。+1/99+1/101)] / 2 = [ 1 - 1/101] / 2 = [100/101] / 2 = 50/101

上一篇 the rest 在句子中作主语谓语用单数还是复数?还是两者都可以用?具体有什么区别?

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