80分~生产任务分配问题~需要方程式和

学习 时间:2026-04-01 07:06:36 阅读:2119
80分~生产任务分配问题~需要方程式和 某构件公司有四个构件厂,现接受五个企业预应力梁和预制桩的订货,订货量分别为2450件和3600件,单价分别是1万元和1.2万元.各构件厂生产能力、单位成本、材料单耗等资料见表12,公司拥有水泥与钢材的数量为25000吨和6500吨,各构件厂所需材料由公司供应,公司到各构件厂的距离为20,35,60,40公里,水泥与钢材的每吨公里运输单价分别为0.2与0.3元.订货企业与各构件厂的距离见表13,预应力梁单件重5吨,预制桩单件重3吨,每吨公里运费1元,建立综合考虑生产费用和运输费用,按公司利润最大建立并求解模型.

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刻苦的鸡翅

传统的学姐

2026-04-01 07:06:36

model:sets:supply/1。。4/:distance1;demand/1。。5/:;goods/1。。2/:tnum,weight,price;link1(supply,demand):distance2;link2(supply,goods):mproduce,cost,cementcost,steelcost;link3(goods,demand):booking;link4(supply,demand,goods):num;endsetsdata:tnum=2450 3600;price=10000 12000;distance1=20 35 60 40;weight=5 3;mproduce=1000 1000800 700500 800450 1200;cost=6000 86006500 85006400 85505950 8700;cementcost=4000 20004050 20504050 20604000 1990;steelcost=1000 6001050 5101030 510990 515;distance2=15 12 19 25 912 18 15 18 1717 10 14 11 1516 9 18 13 20;booking=450 520 600 500 380900 600 1000 500 600;enddatamax=@sum(goods:tnum*price)-@sum(link2(i,j):cost(i,j)*@sum(demand(k):num(i,k,j)))-0。2*@sum(supply(i):distance1(i)*@sum(goods(j):@sum(demand(k):num(i,k,j))*cementcost(i,j)/1000))-0。3*@sum(supply(i):distance1(i)*@sum(goods(j):@sum(demand(k):num(i,k,j))*steelcost(i,j)/1000))-@sum(link1(i,k):distance2(i,k)*@sum(goods(j):weight(j)*num(i,k,j)));@sum(supply(i):@sum(goods(j):@sum(demand(k):num(i,k,j))*cementcost(i,j)))

最新回答共有2条回答

  • 漂亮的秀发
    回复
    2026-04-01 07:06:36

    model:sets:supply/1。。4/:distance1;demand/1。。5/:;goods/1。。2/:tnum,weight,price;link1(supply,demand):distance2;link2(supply,goods):mproduce,cost,cementcost,steelcost;link3(goods,demand):booking;link4(supply,demand,goods):num;endsetsdata:tnum=2450 3600;price=10000 12000;distance1=20 35 60 40;weight=5 3;mproduce=1000 1000800 700500 800450 1200;cost=6000 86006500 85006400 85505950 8700;cementcost=4000 20004050 20504050 20604000 1990;steelcost=1000 6001050 5101030 510990 515;distance2=15 12 19 25 912 18 15 18 1717 10 14 11 1516 9 18 13 20;booking=450 520 600 500 380900 600 1000 500 600;enddatamax=@sum(goods:tnum*price)-@sum(link2(i,j):cost(i,j)*@sum(demand(k):num(i,k,j)))-0。2*@sum(supply(i):distance1(i)*@sum(goods(j):@sum(demand(k):num(i,k,j))*cementcost(i,j)/1000))-0。3*@sum(supply(i):distance1(i)*@sum(goods(j):@sum(demand(k):num(i,k,j))*steelcost(i,j)/1000))-@sum(link1(i,k):distance2(i,k)*@sum(goods(j):weight(j)*num(i,k,j)));@sum(supply(i):@sum(goods(j):@sum(demand(k):num(i,k,j))*cementcost(i,j)))

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