已知椭圆与x2/10+y2/m=1于双曲线x2-y2/b2=1有相同的焦点,且椭圆与双曲线交于p（√10/3,y）,求两

10-m=1+b^2y^2=m(1-x^2/10)=m(1-1/9)=8m/9y^2=b^2(x^2-1)=b^2/9b^2=8mm=1,b^2=8两曲线方程:x^2/10+y^2=1,x^2-y^2/8=1