设函数f(x)在x=x0处的导数不存在,则曲线y=f(x)在x=x0处的极限不存在?

不一定e。gf(x) =|x|f'(0+) = 1,f'(0-) =-1=> f'(0) does not existbutlim(x->0)f(x) = 0