二元一次方程组A1x+B1y=C1 A2x+B2y=C2的解

一式*A2A1*A2x+B1*A2y=C1*A2 (2)二式*A1A2*A1x+B2*A1y=C2*A1 (3)(2)-(3):y=(C1A2-C2A1)/(B1A2-B2A1)一式*B2 A1*B2x+B1*B2y=C1*B2 (4)二式*B1A2*B1x+B2*B1y=C2*B1 (5)(4)-(5):x=(C1B2-C2B1)/(A1B2-A2B1)所以,方程组的解为：x=(C1B2-C2B1)/(A1B2-A2B1)y=(C1A2-C2A1)/(B1A2-B2A1)