化简 cos(@-兀/2)/sin(5兀/2+@)*sin(@-2兀)*cos(2兀-@)

学习 时间:2026-08-29 05:12:04 阅读:7062
化简 cos(@-兀/2)/sin(5兀/2+@)*sin(@-2兀)*cos(2兀-@)

最佳回答

体贴的发带

生动的钥匙

2026-08-29 05:12:04

用sin(2π+a)=sina
cos(2π+a)=cosa
sin(π/2+a)=cosa
cos(a-π/2)/sin(5π/2+a)*sin(a-2π)*cos(2π-a)
=sina/sin(π/2+a)sinacosa
=sin²acosa/cosa
=sin²a

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  • 丰富的棒球
    回复
    2026-08-29 05:12:04

    用sin(2π+a)=sinacos(2π+a)=cosasin(π/2+a)=cosacos(a-π/2)/sin(5π/2+a)*sin(a-2π)*cos(2π-a)=sina/sin(π/2+a)sinacosa=sin²acosa/cosa=sin²a

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