计算:8(72+1)(74+1)(78+1)(716+1)(732+1).

学习 时间:2026-04-08 06:00:35 阅读:4965
计算:8(72+1)(74+1)(78+1)(716+1)(732+1).

最佳回答

有魅力的小伙

贤惠的斑马

2026-04-08 06:00:35

原式=
(7+1)(7−1)(72+1)
6•(74+1)(716+1)(78+1)
=
1
6(72-1)(72+1)(74+1)(78+1)(716+1)(732+1)
=
1
6(74-1))(74+1)(78+1)(716+1)(732+1)
=
1
6(78-1)(78+1)(716+1)(732+1)
=
1
6(716-1)(716+1)(732+1)
=
1
6(732-1)(732+1)
=
1
6(764-1).

最新回答共有2条回答

  • 潇洒的路灯
    回复
    2026-04-08 06:00:35

    原式=(7+1)(7−1)(72+1)6•(74+1)(716+1)(78+1)=16(72-1)(72+1)(74+1)(78+1)(716+1)(732+1)=16(74-1))(74+1)(78+1)(716+1)(732+1)=16(78-1)(78+1)(716+1)(732+1)=16(716-1)(716+1)(732+1)=16(732-1)(732+1)=16(764-1).

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