求极限：lim(x→无穷）（2-x/3-x)的x+2次方

lim(x→∞) [(2-x)/(3-x)]^(x+2)=lim(x→∞) [(3-x-1)/(3-x)]^(x+2)=lim(x→∞) [1-1/(3-x)]^(x+2),之后根据e的定义lim(x→∞) (1+1/x)^x,将原式凑成这形式=lim(x→∞) [1-1/(3-x)]^[-(3-x)]*[-(x+2)/(3-x)],留意指数那是-(3-x),有负号的=e^-lim(x→∞) (x+2)/(3-x),lim(x→∞) [1-1/(3-x)]^[-(3-x)]这个等于e,之后对指数部分求极限=e^-lim(x→∞) (1+2/x)/(3/x-1),分子分母各除以x=e^-(1+0)/(0-1)=e